∆G°37 =
∆G°37(Watson-Crick Helix) + ∆G°37(3' dangling C adjacent to GC) + ∆G°37(5' dangling A adjacent CG)
∆G°37 =
–6.04 kcal/mol
– 0.4 kcal/mol –
0.2 kcal/mol
∆G°37 =
–6.6 kcal/mol
Note that this example contains both a 5' and a 3' dangling end (at opposite ends of the duplex).