Turner 1999
Watson-Crick Helices Example 2

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Turner 1999

Watson-Crick Helices

(Example 2)

 

 

        

∆G°₃₇ = ∆G°_{37 intermolecular initiation} + ∆G°₃₇(GC followed by CG) + ∆G°₃₇(CG followed by AU) + ∆G°₃₇(AU followed by CG) + ∆G°₃₇(CG followed by GC)

 

∆G°₃₇ = 4.09 kcal/mol – 3.42 kcal/mol – 2.11 kcal/mol – 2.24 kcal/mol – 2.36 kcal/mol

 

∆G°₃₇ = –6.04 kcal/mol

 

 

Page Revised 8/02/09