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Turner 1999

Hairpin Loops

Example 4

 

 

example structure        

∆G°37 = ∆G°37(Watson-Crick Pairs) + ∆G°37(Hairpin Loop)

 

∆G°37 = ∆G°37(Watson-Crick Pairs) + ∆G°37(terminal mismatch) + ∆G°37 Hairpin initiation(6) + ΔG°37 penalty (all C loops)

 

∆G°37 = ∆G°37(CG followed by AU) + ∆G°37(AU followed by CG) + ∆G°37(CG followed by AU) + ∆G°37 AU end penalty+ ∆G°37(AU followed by CC) + ∆G°37 Hairpin initiation(6) + 6×A + B

 

∆G°37 = –2.11 kcal/mol 2.24 kcal/mol 2.11 kcal/mol + 0.45 kcal/mol 0.7 kcal/mol + 5.4 kcal/mol + 6×0.3 kcal/mol + 1.6 kcal/mol

 

∆G°37 = +2.1 kcal/mol