Turner 1999

Coaxial Stacking

Example 2



example structure        

∆G°37 coaxial stack = ∆G°37(Continuous Backbone Stack) + ∆G°37(Discontinuous Backbone Stack)


∆G°37 coaxial stack = ∆G°37(AU pair followed by GG mismatch) + ∆G°37(Discontinuous Backbone Stack)


∆G°37 coaxial stack= –0.8 kcal/mol 2.1 kcal/mol


∆G°37 coaxial stack= –2.9 kcal/mol




Note that at this interface, the terminal AU pair penalty would still apply when calculating the helix stability.