Turner 2004
Watson-Crick Helices Example 2

Navigator:

Homepage

Turner 2004

Watson-Crick Helices

(Example 2)

 

 

        

∆G°₃₇ = ∆G°_{37 intermolecular initiation} + ∆G°₃₇(GC followed by CG) + ∆G°₃₇(CG followed by AU) + ∆G°₃₇(AU followed by CG) + ∆G°₃₇(CG followed by GC)

 

∆G°₃₇ = 4.09 kcal/mol – 3.42 kcal/mol – 2.11 kcal/mol – 2.24 kcal/mol – 2.36 kcal/mol

 

∆G°₃₇ = –6.04 kcal/mol

 

∆H°= ∆H°_{intermolecular initiation} + ∆H°(GC followed by CG) + ∆H°(CG followed by AU) + ∆H°(AU followed by CG) + ∆H°(CG followed by GC)

 

∆H°= 3.61 kcal/mol – 14.88 kcal/mol – 10.44 kcal/mol – 11.40 kcal/mol – 10.64 kcal/mol

 

∆H°= –43.75 kcal/mol

 

Page Revised 7/21/09