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Turner 2004

Terminal Mismatches

Example

 

 

example structure        

∆G°37 = ∆G°37(Watson-Crick Helix) + ∆G°37(UA followed by GA)

 

∆G°37 = –7.94 kcal/mol – 1.1 kcal/mol

 

∆G°37 = –9.0 kcal/mol

 

∆H°= ∆H°(Watson-Crick Helix) + ∆H°(UA followed by GA)

 

∆H°= –50.31 kcal/mol – 3.8 kcal/mol

 

∆H°= –54.1 kcal/mol